Grade 9 - Solve for x

Yesterday we did a note to solve for x. Example: 3x - 17 = 28 and 4 - 5k = 8 + k

5t = 25

Pg. 269 1acegik, 2aceg, 8acegik, 10acegik

Today we did word problems involving forming an equation.
It is crucial to start with "let" statements to indicate what your variables stand for. Example in class:
We are getting married and deciding how many guests to invite. We have two venues as options; 1 charges 650 for the hall rental and 32 per person. The other charges 850 and 52 per person. We think things over and decide if we go with option 1 we will invite all 90 family members and a selected list of 62 if we go for the second classier option.
Create the two equations and solve for the total cost. Explain which hall you would chose.
a) Let C be the total cost
Let n be the number of guests.

C=650 + 32n (Option 1) C = 850 + 52n (Option 2)
Sub in n = 90 Sub in n = 62
C = 650 + 32(90) C = 850 + 52(62)
C = 650 + 2880 C = 850 + 3224
C = 3530 C = 4074

Therefore, we will choose option 1 as it is both cheaper and we can invite ALL the family ;)

pg. 269-271 #4, 5, 7, 11, 12 (13 is bonus)